Table of Contents
Introduction
In this program, you will learn to calculate the sum of the digits of the integer value entered by the user in the C++ language.
For example, the number is 98542, and then this code will add all the digits of 98542 i.e., 9+8+5+4+2=28, and return 28 as output.
To understand the program, learn the following basic concepts of C++ programming
1. Operators
2. while and do-while loop
Program
#include<iostream>
using namespace std;
int main()
{
int n;
cout<<"Enter a integer: ";
cin>>n;
int rem=0; // rem is used for remainder
int sum=0;
while(n!=0)
{
rem=n%10; // fetching the last digit
sum=sum+rem; // rem is added to sum
n=n/10; // elimination of last digit
}
cout<<"Sum: "<<sum;
return 0;
}
Output
Explanation
‘n’ will store the integer entered by the user.
int rem=0;
‘rem’ variable is initialized with a 0 value to find the remainder.
int sum=0; ‘sum’ variable is initialized with a 0 value to hold the sum of the digits.
The value of ‘n’ is 895412
while(n!=0)
the above condition is true
rem=n%10; this will return rem=895412%10=2
sum=sum+rem;
Since the sum is 0, therefore from the above statement, z=0+2=2
n=n/10; the value of ‘n’ is updated to 895412/10=89541, thus vanishes the last digit.
Again, the condition in the while loop will become true, and the same procedure will take place for n=89541
rem=89541%10=1
sum=2+1=3
n=89541/10=8954
Again, the condition in the while loop will become true, and the same procedure will take place for n=8954
rem=8954%10=4
sum=3+4=7
n=8954/10=895
Again, the condition in the while loop will become true, and the same procedure will take place for n=895
rem=895%10=5
sum=7+5=12
n=895/10=89
Again, the condition in the while loop will become true, and the same procedure will take place for n=89
rem=89%10=9
sum=12+9=21
n=89/10=8
Again, the condition in the while loop will become true, and the same procedure will take place for n=8
rem=8%10=8
sum=21+8=29
n=8/10=0
The loop gets terminated when n becomes equal to 0.
Thus ‘sum’=29
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