Table of Contents

## Introduction

In this example, we will explore calculating the power of a number.

The user will be asked to enter an integer as the base value and the power value which will be the exponent of the base number.

For example, 9 raised to the power 3 means 9*9*9=721, where 9 is the base value and 3 is the exponent.

To understand the program, you should know about

1. Operators in C

2. while and do while loop in C

## Program

#include<stdio.h> int main() { float b; // b is base number printf("Enter a base number\n"); scanf("%f",&b); int p; // p is the power or exponent printf("Enter an exponent\n"); scanf("%d",&p); float result=1; while(p!=0) //condition { result=result*b; p--; } printf("Result = %.2f",result); return 0; }

## Output

## Explanation

‘b’ is the variable for the base number and ‘p’ is the power of the base number.

**float result=1;**

To store the final result variable ‘result’ is initialized with 1.

**while(p!=0) **

If the above condition gives a true result then the body of the while loop is executed.

Since ‘p’ is 3 thus the condition becomes true and the value of the base entered by the user is 9.2 therefore,

**result=result*b;** it will assign 1*9.2 i.e., result=9.2000

**p–; **‘p’ gets decremented to 2

the condition becomes true for p=2 thus,

**result=result*b;** it will assign 9.2000*9.2 i.e., result=84.6400

**p–; **‘p’ gets decremented to 1

the condition becomes true for p=1 thus,

**result=result*b;** it will assign 84.6400*9.2 i.e., result=778.6880

**p–; **‘p’ gets decremented to 0

the condition becomes false for p=0 thus,

the final result is 778.6880

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