Table of Contents
Introduction
In this example, we will explore calculating the power of a number.
The user will be asked to enter an integer as the base value and the power value which will be the exponent of the base number.
For example, 9 raised to the power 3 means 9*9*9=721, where 9 is the base value and 3 is the exponent.
To understand the program, you should know about
1. Operators in C
2. while and do while loop in C
Program
#include<stdio.h>
int main()
{
float b; // b is base number
printf("Enter a base number\n");
scanf("%f",&b);
int p; // p is the power or exponent
printf("Enter an exponent\n");
scanf("%d",&p);
float result=1;
while(p!=0) //condition
{
result=result*b;
p--;
}
printf("Result = %.2f",result);
return 0;
}
Output
Explanation
‘b’ is the variable for the base number and ‘p’ is the power of the base number.
float result=1;
To store the final result variable ‘result’ is initialized with 1.
while(p!=0)
If the above condition gives a true result then the body of the while loop is executed.
Since ‘p’ is 3 thus the condition becomes true and the value of the base entered by the user is 9.2 therefore,
result=result*b; it will assign 1*9.2 i.e., result=9.2000
p–; ‘p’ gets decremented to 2
the condition becomes true for p=2 thus,
result=result*b; it will assign 9.2000*9.2 i.e., result=84.6400
p–; ‘p’ gets decremented to 1
the condition becomes true for p=1 thus,
result=result*b; it will assign 84.6400*9.2 i.e., result=778.6880
p–; ‘p’ gets decremented to 0
the condition becomes false for p=0 thus,
the final result is 778.6880
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