Table of Contents
Introduction
This article demonstrates how you can check if the entered year is a leap year or not with the help of a Java program. Although the problem looks quite easy at first, the computation is a bit tricky. We can easily assume that all leap years are multiples of 4. That is, if a particular year is divisible by 4 with no remainder, then the year is a leap year. However, this is a naïve implementation of the leap year program. A year can also be a leap year if the following conditions are met:
- A year is a leap year if it gets divisible by 100.
- If a particular year is divisible by 100, then it also must be divisible by 400.
- Other than the two conditions given above, if any other year is divisible by 4, that year is also surely a leap year.
Algorithm
- Start
- Initialize an integer variable called year. This variable will decide whether a year is a leap year or not.
- If the condition checks whether the variable is divisible by 4 but not 100. If the condition is true, ‘leap year’ is printed out to the console.
- If the year gets divisible by 400, then ‘leap year’ is again printed out to the console.
- For all other cases except the ones defined above, print ‘not a leap year’.
Sample Code to implement the Leap Year Problem
import java.util.Scanner;
public class Demo
{
public static void main ( String args [] )
{
int year;
System.out.println (“Enter a Year :: ”);
Scanner sc = new Scanner (System.in);
year = sc.nextInt ();
if ( ( ( year % 4 == 0 ) && ( year % 100! = 0 ) ) || ( year % 400 == 0 ) )
System.out.pintln ( “ The specified year is a leap year ” );
else
System.out.println ( “The specified year is not a leap year ” );
}
}
OUTPUT 1:
Enter a Year:: 2020
The specified year is a leap year
OUTPUT 2:
Enter a Year:: 2017
The specified Year is not a leap year
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