# Program to check Armstrong Number in Python

## Introduction

In this section we’ll learn to check whether the given number is Armstrong number or not. A number is said be Armstrong number of order n if:

abc….n = power(a,n) + power(b,n) + power(c,n) +……..+ powe(n,n) ## Program

```# Function to calculate the power b of number a
def pow(a,b):
if b == 0:
return 1
if b%2 == 0:
return pow(a,b//2)*pow(a,b//2)
return a*pow(a,b//2)*pow(a,b//2)

#Function to calculate the order of number
def ord(order):
x = 0
while(order!=0):
x += 1
order = order//10
return x

#Check Armstrong number
def check_Armstrong(n):
x = ord(n)
temp = n
sum_res = 0
while(temp!=0):
temp1 = temp%10
sum_res = sum_res+pow(temp1,x)
temp = temp//10
return (sum_res == 0)

n = 268
print(check_Armstrong(n))```

Output: ## Explanation

In the above program, we have created three functions pow(), ord() and check_armstrong(). The pow() function will calculate the power of digits, ord() function will calculate the order of number i.e. the number of digits in a given number and the check_armstrong() function will verify whether the it is Armstrong number or not. The function check_armstrong() returns the boolean value depending upon the given number.

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