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# Program to check Armstrong Number in Python

by | Jan 15, 2021 | Python Programs

Home » Python » Python Programs » Program to check Armstrong Number in Python

## Introduction

In this section we’ll learn to check whether the given number is Armstrong number or not. A number is said be Armstrong number of order n if:

abc….n = power(a,n) + power(b,n) + power(c,n) +……..+ powe(n,n) ## Program

```# Function to calculate the power b of number a

def pow(a,b):

if b == 0:

return 1

if b%2 == 0:

return pow(a,b//2)*pow(a,b//2)

return a*pow(a,b//2)*pow(a,b//2)

#Function to calculate the order of number

def ord(order):

x = 0

while(order!=0):

x += 1

order = order//10

return x

#Check Armstrong number

def check_Armstrong(n):

x = ord(n)

temp = n

sum_res = 0

while(temp!=0):

temp1 = temp%10

sum_res = sum_res+pow(temp1,x)

temp = temp//10

return (sum_res == 0)

n = 268

print(check_Armstrong(n))```

Output: ## Explanation

In the above program, we have created three functions pow(), ord() and check_armstrong(). The pow() function will calculate the power of digits, ord() function will calculate the order of number i.e. the number of digits in a given number and the check_armstrong() function will verify whether the it is Armstrong number or not. The function check_armstrong() returns the boolean value depending upon the given number.

## Author

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