Introduction

The task is to find the occurrence of days Monday, Tuesday, Wednesday, Thursday, Friday, Saturday and Sunday in a given year.

Program

import datetime
import calendar


def occurence(ip_year):
    week_days = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday", "Sunday"]
    list = [52 for i in range(7)]
    idx = -1
    day = datetime.datetime(ip_year, month = 1, day = 1).strftime("%A")
    for i in range(7):
        if day == week_days[i]:
            idx = i
        if calendar.isleap(ip_year):
            list[idx] += 1
            list[(idx+1)%7] += 1
        else:
            list[idx] += 1
        for i in range(7):
            print(week_days[i], list[i])
           
ip_year = int(input("Enter the year: "))
print("The count of days in year {0} is:".format(ip_year))
occurence(ip_year)

Output

Explanation

As we know that in a particular year we have at least 52 weeks. That means each day will occur at least 52 times in a year. We have created a list of size 7 with initial value 52. We have found the index of the first day of the given year. It the year is found to be leap year, increment the first day and second day by 1. At last calculate the number of days with occurrence and print the result.