# Program to find sum of even factors of the given number using Python

## Introduction

The task is to find and print sum of even factors of the give number.

## Program

```import math

def findsum(ip_num) :

#No even factor for odd input

if (ip_num % 2 != 0) :

return 0

op_sum = 1

for num in range(2, int(math.sqrt(ip_num)) + 1) :

i = 0

temp = 1

temp1 = 1

while (ip_num % num == 0) :

i = i + 1

ip_num = ip_num // num

if (num == 2 and i == 1) :

temp = 0

temp1 = temp1 * num

temp = temp + temp1

op_sum = op_sum * temp

#If n is prime

if (ip_num >= 2) :

op_sum = op_sum * (1 + ip_num)

return op_sum

ip_num = int(input("Enter the number: "))

print("The sum of even factors of given number is: ",findsum(ip_num))```

## Explanation

If the given number is odd there is no even factor of it. For example, let us take 27, the factors of 27 are 1, 3, 9, 27. There is no even factor of 27 so we return 0.

We can write the number as

`(n1p1 ) * (n2p2 )…… (nnpn ) or (1+ n1+n12+n13+…..n1p1) * (1+ n2+n22+n23+…..n1p2) *……. *(1+ nn+nn2+n13+…..nnpn). To get the sum of even number we need to ignore n0 value (i.e. 1).`

## Author

• A Full Stack Developer with 10+ years of experience in different domain including SAP, Blockchain, AI and Web Development.