Table of Contents
Introduction
The task is to find the most occurring number in the given string using regex expression.
Program
from collections import Counter
import re
def frequent_no(ip_str):
arr = re.findall(r'[0-9]+', ip_str)
max_freq = 0
ele = 0
count = Counter(arr)
for i in list(count.keys()):
if count[i]>=max_freq:
max_freq = count[i]
ele = int(i)
return ele
ip_str = input("Enter the string: ")
print("The most frequent number in the string {0} is {1}". format(ip_str, frequent_no(ip_str)))
Output
Explanation
In the above python code our approach is:
- Extract all the numbers from the given string using regex expression.
- Using Counter() function we stored all the numbers with their frequency of occurrence.
- And then we used loop on counter() result to get the most occurred number in the string.
0 Comments